化简:
(1)(8xy-x2+y2)-4(x2-y2+2xy-3);
(2)
.
答案
(1)-5x2+5y2+12;
(2)-2a2b.
知识点:整式的加减

(1)(8xy-x2+y2)-4(x2-y2+2xy-3)
=8xy-x2+y2-4x2+4y2-8xy+12
=(-1-4)x2+(1+4)y2+12
=-5x2+5y2+12;
(2)3a2b-[4ab2-3(ab2+a2b)-ab2]-6a2b
=3a2b-4ab2+3(ab2+a2b)+ab2-6a2b
=3a2b-4ab2+3ab2+a2b+ab2-6a2b
=-2a2b.

略
